Which leaves a black residue on heating?

Which leaves a black residue on heating?

Copper sulfate is normally found in the form of blue crystals, copper (II) sulfate pentahydrate. When you heat copper sulfate pentahydrate it turns white as the water which is driven off by the heat. The white solid remaining is anhydrous copper sulfate. On further heating, it changes to black color.

What is the Colour of lead nitrate crystals?

white

What is the residue left when lead nitrate is heated?

When lead nitrate is heated, it decomposes to give lead oxide, nitrogen dioxide and oxygen. Lead oxide is a yellow coloured solid, while nitrogen dioxide is a brown coloured gas. The chemical equation involved in the reaction is : Hence, the colour of the residue obtained by heating lead nitrate is yellow.

What is the brown Coloured gas evolved when lead nitrate?

nitrogen dioxide

How will you obtain nitrogen dioxide from lead nitrate?

Lead nitrate on heating decomposes to lead monoxide, nitrogen dioxide and oxygen. NO2 is liberated, along with oxygen, as a reddish brown gas. The residue left is lead monoxide. PbO is lead oxide,nitrogen dioxide[NO2] which appears as brown fumes and oxygen is produced.

What happens when crystals of feso4 are heated?

On heating, ferrous sulphate crystals lose water and anhydrous ferrous sulphate (FeSO4) is formed. On further heating, anhydrous ferrous sulphate decomposes to form ferric oxide (Fe2O3), sulphur dioxide (SO2) and sulphur trioxide (SO3).

When crystals of FeSO4 are strongly heated the residue obtained is?

When ferrous sulphate is heated, it gives ferric oxide, sulphur dioxide and sulphur trioxide.

When ferrous sulphate crystals are heated the residue left behind is?

On heating ferrous sulphate it decomposes into ferric oxide Fe2O3 (residue) which is red in colour.

Is decomposition of FeSO4 redox reaction?

So, the gas emitted smells like burning sulphur. > It is evident from the reaction that the single reactant (FeSO4) decomposes to form three different products. Therefore, the reaction is a decomposition reaction. Since, Fe(II) is oxidized to Fe(III) and S (VI) is reduced to S (IV), it is a redox reaction.